1.67 x10 27
a proton (mass = .xkg) is confined in a onedimensional potential well of infinite height and width of x meter. (this is onthe order of the size of an atomic nucleus.) calculate the kineticenergy of the proton in the state with quantum number in mev. answer is. mev
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answer to a proton (mass = .x kg, charge = .x c) is accelerated from rest through a potential difference of v. atomic and nuclear masses. the masses of atoms and subatomic particles are extremely small for example the mass of an oxygen atom is about x kg and that of a neutron about .x kg. it is therefore convenient to define a new unit to measure them. this is known as the atomic mass unit written as a.m.u or
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) déterminer le numéro atomique z et le nombre de nucléon a du noyau, en déduire le nombre de neutrons. ) s'agitil d'un atome ou d'un ion ? données: la charge élémentaire e= .x c masse d'un proton: mp = .x kg. j'ai un problème, j'ai trouvé le nombre de protons (z): q=zxe z=q/e m = p x henry/meter. permittivity of free space: e = . x farad/meter = . x farad/centimeter. planck's constant: h = . x joule second = . x electron volt second. proton rest mass: m = . x kilogram. rydberg constant: r = . x joule = . electron
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.x j k. .x erg k. .x ev k. .. stephanboltzman. s. .x j m s k. .x erg cm s k. ev m s k. .. radiation constant. a. .x j m k. .x erg cm k. ev m k. proton mass. mp. .x kg. il a donc nucléons (a), protons (z), neutrons (az = = neutrons) et électrons. déterminer la masse de l'atome de fer et de son noyau. j'ai mis comme mnucléon = .x (moins est en exposant) kg alors m n = x . x kg = . x kg et me = . x kg
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exercice : l'atome d'hydrogène h est le plus simple des atomes.son noyau comporte un charge positive (appelée proton) de masse .xkg.( le est un électron) gravite autour du noyau un topic dm de chimie ème !!! du :: sur les forums de jeuxvideo. vv m note — the potential difference required to have an electron of wavelength x a is — . a. () for protons (mp= . x (t kg) . v = (from above equation) x = vv () for deuterons (m^= x . x . kg) x = vv () for aparticles (ma = x . x ~ kg) x = — a vv electron microscope it is a
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problem: determine the boundstate energy levels for a proton bound by two (attractive) functions of strength s = .x' jm separated by a = .x' m. _s _ ~ given: —s = .x j—m figure: e a = .xi' m m = .x' kg e find: the boundstate energy levels, e and e |q ______a
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